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Law of Reciprocal

Solve: 3x+2...

Question

Solve: $3 x + 2 y \leq 24, x + 2 y \leq 16, x + y \leq 10, x \geq 0, y \geq 0$ .

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Solution

$3 x + 2 y \leq 24$ ..(1)
$x + 2 y \leq 16$ ...(2)
$x + y \leq 10$ ..(3)
Solving (1) and (2) we get $x \leq 4$
$x + y \leq 10$
when $x = 4$
$4 + y \leq 10$
$y \leq 10 - 4$
$y \leq 6$
$y \geq 0$
$x \leq 4$
$x \geq 0$
$x \leq 4$ and $y \leq 4$

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