Solve:
$3 x + 4 y = 10$ and $2 x - 2 y = 2$

x = - 1, y = 1

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x = 2, y = - 1

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x = 3, y = 1

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x = 2, y = 1

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Solution

The correct option is D $x = 2, y = 1$
$3 x + 4 y = 10$ ...(i)
$2 x - 2 y = 2$ ...(ii)
Multiplying equation (2) by (2) and then adding then adding
$3 x + 4 y = 10$
$+ 4 x - 4 y = 4$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 7 x = 14$
$∴ x = \frac{14}{7} = 2$
$∴ x = 2$
Now, $3 (2) + 4 y = 10$
$∴ y = \frac{10 - 6}{4}$
$∴ y = \frac{4}{4} = 1$
$∴ y = 1$
Ans:- The value of $x$ is $2$
The value of $y$ is $1$

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