Solve: $3 x + 5 < x - 7,$ when $x$ is real number

x < - 6

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x > - 6

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x < - 12

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x > - 12

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Solution

The correct option is A $x < - 6$
Given, $3 x + 5 < x - 7$
$\Rightarrow 2 x < - 12$
$\Rightarrow x < - 6$
Hence, the answer is option A.

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