Question

Solve 3x + 8 > 2 when

(i) x is integer

(it) x is a real number

Answer 1

Here 3x + 8 > 2

$\Rightarrow 3x>2-8\Rightarrow 3x>-6$

Dividing both sides by 3, we have x > - 2

(i) When x is an integer then values of x that make the statement true are -1, 0, 1, 2, 3, ... The solution set of inequality is {-1, 0, 1, 2, 3, ... }.

(ii) When x is a real number. The solution set of inequality is $x\in (-2,\infty )$.