Question

Solve:$3x+\frac{1}{2}=\frac{3}{8}+\frac{x}{4}$

Answer 1

$3x+\frac{1}{2}=\frac{3}{8}+\frac{x}{4}$

$\Rightarrow 3x-\frac{x}{4}=\frac{3}{8}-\frac{1}{2}$

$\Rightarrow \frac{12x-x}{4}=\frac{3}{8}-\frac{4}{8}$

$\Rightarrow \frac{11x}{4}=\frac{-1}{8}$

$\Rightarrow 11x=\frac{-4}{8}=\frac{-1}{2}$

$\therefore x=\frac{-1}{22}$