Question

Solve: $\sqrt{3}{x}^2+11x+6\sqrt{3}=0$

Answer 1

$$\begin{gathered} \sqrt{3}{x}^2+11x+6\sqrt{3}=0 \\ \text{⇒}\sqrt{3}{x}^2+9x+2x+6\sqrt{3}=0 \\ \text{⇒}\sqrt{3}x(x+3\sqrt{3})+2(x+3\sqrt{3})=0 \\ \text{⇒}(x+3\sqrt{3})(\sqrt{3}x+2)=0 \\ \therefore x=-3\sqrt{3},x=-\frac{2}{\sqrt{3}} \end{gathered}$$