Solve: $3 y^{2} - 118 y + 16 = 3 y^{2} + 2 y - 4$ . Find the value of $12 y$ .

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Solution

$3 y^{2} - 118 y + 16 = 3 y^{2} + 2 y - 4 - 120 y = - 20 y = \frac{1}{6} 12 y = 12 \times \frac{1}{6} = 2$

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