Question

Solve:

$\frac{(3y+4)}{(2-6y)}=\frac{-2}{5}$

Answer 1

we have, $\frac{(3y+4)}{(2-6y)}=\frac{-2}{5}$

cross multiply

$$\begin{gathered} \Rightarrow 5(3y+4)=-2(2-6y) \\ \Rightarrow 15y+20=-4+12y \\ \Rightarrow 3y=-24 \\ \Rightarrow y=-8 \end{gathered}$$

Hence, the required answer is$y=-8$ .