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Question

Solve :
(3y7x+7) dx+(7y3x+3) dy=0

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Solution

Given,

(3y7x+7)dx+(7y3x+3)dy=0

(3y)dx(7x)dx+7dx+(7y)dy(3x)dy+3dy=0

Upon integration, we get,

3yx72x2+7x+72y23xy+3y=0

7x+3y72(x2y2)=0

7x+3y=72(x2y2)

14x+6y=7x27y2

7x27y214x6y=0

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