Question

Solve: $(x-4)(2x+3)=2x^2$

Answer 1

Step: Find the value of x

We have,

$(x-4)(2x+3)=2x^2$

After removing the brackets we get,

$x(2x+3)-4(2x+3)=2x^2$

Simplifying the calculation further we get,

$x\times 2x+3x-4\times 2x-4\times 3=2x^2$

$\Rightarrow 2x^2+3x-8x-12=2x^2$

Now, transposing the terms $2x^2$ and 12 to RHS we get,

$3x-8x=2x^2-2x^2+12$

$\Rightarrow -5x=12$

Now, transposing the term -5 to RHS we get,

$x=(-12)/5$

∴ The value of 𝑥 = $\frac{-12}{5}$ .