Question

Solve:
$4-3x-2x^2$=0

Answer 1

$\sqrt{4-3x-2x^2}=0$

$\Rightarrow$ $4-3x-2x^2=0$

$\Rightarrow$ $2x^2+3x-4=0$

$\Rightarrow$ Here, $a=2,b=3,c=-4$

$\Rightarrow$ $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\frac{-3\pm \sqrt{(3{)}^2-4(2\left)\right(-4)}}{2\left(2\right)}$

$=\frac{-3\pm \sqrt{9+32}}{4}$

$=\frac{-3\pm \sqrt{41}}{4}$

$x=\frac{-3+\sqrt{41}}{4}$ and $x=\frac{-3-\sqrt{41}}{4}$