Question

Solve: $4-\frac{2(z-4)}{3}=\frac{1}{2}(2z+5)$

Answer 1

Given $4-\frac{2(z-4)}{3}=\frac{1}{2}(2z+5)$
$\Rightarrow 4-\frac{2z}{3}+\frac{8}{3}=z+\frac{5}{2}$
Grouping $z$ terms and constant terms, we get
$\Rightarrow 4+\frac{8}{3}-\frac{5}{2}=z+\frac{2z}{3}$
$\Rightarrow \frac{24+16-15}{6}=\frac{3z+2z}{3}$

$\Rightarrow \frac{25}{6}=\frac{5z}{3}$
$\Rightarrow z=\frac{25}{6}\times \frac{3}{5}$
$\therefore z=\frac{5}{2}$