Question

Solve :
$4x-19y+13=0,13x-23y=-19$

Answer 1

$4x-19y+13=0$...(1)

$13x-23y=-19$...(2)

from eqn. (1)

$x=\frac{19y-13}{4}$...(3)

Put in eqn (2)

$13\left[\frac{19y-13}{4}\right]-23y=-19$

$247y-169-92y=-76$

$155y=93$

$y=\frac{3}{5}$

put in eqn (3)

$x=\frac{19\times \frac{3}{5}-13}{4}$

$x=\frac{57-65}{20}$

$x=\frac{-8}{20}=-\frac{2}{5}$