Question

Solve:
$4x^2-3x+7=0$

Answer 1

We have,

$4x^2-3x+7=0$

We have a formula for solving quadratic equation $a{x}^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Therefore,

$x=\frac{-(-3)\pm \sqrt{(-3{)}^2-4\times 4\times 7}}{2\times 4}$

$x=\frac{3\pm \sqrt{9-112}}{8}$

$x=\frac{3\pm \sqrt{-103}}{8}$

Hence, this is the answer.