Question

Solve: $4x^2+4\sqrt{3}x+3=0$

Answer 1

given, $4x^2+4\sqrt{3}x+3$

$=4x^2+2\sqrt{3}x+2\sqrt{3}x+3$

$=2x(2x+\sqrt{3})+\sqrt{3}(2x+\sqrt{3})$

$(2x+\sqrt{3})(2x+\sqrt{3})$

$x=\frac{-\sqrt{3}}{2},\frac{-\sqrt{3}}{2}$