Solve: $4 + y - 14 y^{2} = 0$

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Solution

$4 + y - 14 y^{2} = 0$
$14 y^{2} - y - 4 = 0$
$\Rightarrow y = \frac{1 \pm \sqrt{1 + 2^{2} 4}}{28}$
$= \frac{1 \pm 15}{28}$
$= \frac{1}{2}, \frac{4}{7}$

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