Given, #160; ( 48p^4)÷( 9p^2) We can write it as: 48 p^ 4 9 p^ 2 =489×p^4p^2 We know that, a^ma^n=a^m n Hence, 489× p^4 2 163× ...

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Laws of Exponents for Real Numbers

Solve: -48p4...

Question

Solve:
$(- 48 p^{4}) \div (- 9 p^{2})$

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Solution

Given, $(- 48 p^{4}) \div (- 9 p^{2})$

We can write it as:
$\frac{- 48 p^{4}}{- 9 p^{2}}$

$= \frac{48}{9} \times \frac{p^{4}}{p^{2}}$

We know that, $\frac{a^{m}}{a^{n}} = a^{m - n}$

Hence, $\frac{48}{9} \times p^{4 - 2}$

$\frac{16}{3} \times p^{2}$

$= \frac{16 p^{2}}{3}$

Hence, $(- 48 p^{4}) \div (- 9 p^{2}) = \frac{16 p^{2}}{3}$ .

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