Question

Solve: $(4pq+3q{)}^2-(4pq-3q{)}^2$ = ______________

Answer 1

By applying $(a+b{)}^2=a^2+2ab+b^2,$ and $(a-b{)}^2=a^2-2ab+b^2$ in the given expression, we get,

${(4pq+3q)}^2-{(4pq-3q)}^2$
$=[{\left(4pq\right)}^2+{\left(3q\right)}^2+2(4pq\left)\right(3q\left)\right]$
$-[{\left(4pq\right)}^2+{\left(3q\right)}^2-2(4pq\left)\right(3q\left)\right]$
On simplifying, we get,
$=24p{q}^2+24p{q}^2$
$=48p{q}^2$
$\left[2Marks\right]$