Question

Solve
$4x^2-7x+5$

Answer 1

Formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Given,

$4x^2-7x+5=0$

Therefore,

$x=\frac{-(-7)+\sqrt{{(-7)}^2-4\cdot 4\cdot 5}}{2\cdot 4}$

$=\frac{7\pm \sqrt{31}i}{8}$

$x=\frac{7}{8}\pm i\frac{\sqrt{31}}{8}$

Hence, this is the answer.