Given equation, 4x^2 8x + 4 Now, [ 4 x^ 2 4x 4x+4=0; 4x( x 1 ) 4( x 1 ) =0; 4x 4=0,x 1=0; 4x=4 x=1 ] Hence,We g ...

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Sequence

Solve: 4x2-8...

Question

Solve:
$4 x^{2} - 8 x + 4$

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Solution

Given equation,
$4 x^{2} - 8 x + 4$
Now,
$\begin{matrix} 4 x^{2} - 4 x - 4 x + 4 = 0 4 x (x - 1) - 4 (x - 1) = 0 4 x - 4 = 0, x - 1 = 0 4 x = 4 x = 1 \end{matrix}$
Hence,
We get the values of given equation is $x = 1$

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