Solve 4x + 3 < 6x + 13, where $x$ is natural no. less than 3.

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Solution

We have $4 x + 3 < 6 x + 13$
or $4 x - 6 x < 6 x + 10 - 6 x$
or $- 2 x - 10 < 0$ or $2 x + 10 > 0$ $\Rightarrow x + 5 > 0$
i.e. all the natural which are greater than -5 are the solutions of the given inequality Hence the solution set is $1, 2$

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