1
Question
Solve:
4x4−5x3−7x+1÷4x−1
4x4−5x3−7x+1÷4x−1
Open in App
Solution
We have,4x−1)4x4−5x3−7x+1(x3−x2−x4−2916−4x4−x3––––––––––––−4x3−7x−−4x3+x2–––––––––––––−x2−7x−−x2+x4––––––––––––––−294x+1−−294x+2916––––––––––––−1316Quotient x3−x2−x4−2916Remainder −1316
4x−1)4x4−5x3−7x+1(x3−x2−x4−2916−4x4−x3––––––––––––−4x3−7x−−4x3+x2–––––––––––––−x2−7x−−x2+x4––––––––––––––−294x+1−−294x+2916––––––––––––−1316
Quotient x3−x2−x4−2916
Remainder −1316
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
