Solve
$(4 x + 5) (3 x + 7)$

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Solution

(4x+5)(3x+7)
$12 x^{2} + 28 x + 15 x + 15 x + 35$
$= 12 x^{2} + 43 x + 35$
This is the quadratic equation .

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Similar questions

Solve:-

(i) $5 (3 x - 4) - 8 (6 x - 7) = 9 x - 8$

(ii) $2 x - \frac{3 x}{5} = 7$

(iii) $\frac{2 z}{3} - 5 = \frac{3 z}{4} - 1$

(iv) $\frac{4 x}{7} - 12 = 7$

x

\frac{1}{5} (3 x - 2) - \frac{1}{3} (x + 7) + 1 = 0

Solve for x and y:

$\frac{1}{2 (3 x + y)} + \frac{5}{3 (3 x - y)} = \frac{- 3}{2} \frac{5}{4 (x + 2 y)} - \frac{3}{5 (3 x - 2 y)} = \frac{61}{60} .$

Solve the following systems of equations:

$\frac{1}{2 (x + 2 y)} + \frac{5}{3 (3 x - 2 y)} = \frac{- 3}{2}$

$\frac{5}{4 (x + 2 y)} - \frac{5}{5 (3 x - 2 y)} = \frac{61}{60}$

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