Solve $4 x + 5 y + 9 = 0$ and $3 x + 4 y + 8 = 0$

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Solution

Given $4 x + 5 y + 9 = 0$ .........(1)
$3 x + 4 y + 8 = 0$ ........... (2)
$\frac{x}{5 \times 8 - 4 \times 9} = \frac{y}{3 \times 9 - 4 \times 8} = \frac{1}{4 \times 4 - 3 \times 5}$
$\frac{x}{4} = \frac{y}{- 5} = \frac{1}{1}$
or $x = 4, y = - 5$

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