Question

Solve: $4x+\frac{6}{y}=15$ and $6x-\frac{8}{y}=14$

• A. $x=2;y=3$
• B. $x=3;y=2$
• C. $x=1;y=5$
• D. $x=4;y=1$

Answer 1

The correct option is B $x=3;y=2$

Given equations are
$4x+\frac{6}{y}=15$ ...(1)

$6x-\frac{8}{y}=14$ ...(2)

Multiplying equation $\left(1\right)$ with $6$ we get,

$24x+\frac{36}{y}=90$ ...(3)

Multiplying equation $\left(2\right)$ with $4$ we get,

$24x-\frac{32}{y}=56$ ...(4)

Subtracting eq(4) from eq(3) we get,

$\frac{68}{y}=34=>y=2$

Substituting $y=2$ in eq(1) we get,

$4x+\frac{6}{2}=15=>x=3$