Question

Solve: $5\sqrt{5}{x}^2+20x+3\sqrt{5}=0$

Answer 1

Now,

$5\sqrt{5}{x}^2+20x+3\sqrt{5}=0$

or, $5\sqrt{5}{x}^2+15x+5x+3\sqrt{5}=0$

or, $\sqrt{5}x(5x+3\sqrt{5})+1(5x+3\sqrt{5})=0$

or, $(\sqrt{5}x+1)(5x+3\sqrt{5})=0$

or, $x=-\frac{1}{\sqrt{5}},-\frac{3}{\sqrt{5}}$.