Concept: 1 Mark
Application: 1 Mark
Answer: 2 Marks
We have,
5x+1+52−x=53+1
⇒5x×5+52×5−x=126
⇒5x×5+255x=126......(1)
Let 5x=y
Then (1) reduces to,
⇒5y+25y=126
⇒5y2−126y+25=0
⇒5y2−125y−y+25=0
⇒5y(y−25)−1(y−25)=0
⇒(y−25)(5y−1)=0
⇒y−25=0 or 5y−1=0
⇒y=25 or y=15
⇒5x=25 or 5x=15
⇒5x=52 or 5x=5−1
⇒x=2 or x=−1
∴ Roots of the equation are 2 and -1.