Question

Solve:
$5x^2-4x-5=0$

Answer 1

$5x^2-4x-5=0$

or, $x=\frac{4\pm \sqrt{16+\mathrm{4.5.5}}}{10}$

or, $x=\frac{4\pm \sqrt{116}}{10}$

or, $x=\frac{4\pm \sqrt{4\times 29}}{10}$

or, $x=\frac{2\pm \sqrt{29}}{5}$