Question

Solve: $5x^2=4x+7$

Answer 1

$5x^2-4x-7=0$

$b^2-4ac$

$(-4{)}^2-4X5X-7$

$16+140$

$=156$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-\left(4\right)\pm \sqrt{156}}{25}$

$x=\frac{-4\pm 12.48}{10}$