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Question

Solve:

[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]


A

27

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B

39

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C

31

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D

0

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Solution

The correct option is B

39


[[5×{(−3)×(−4)}]÷{27+(−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]

Applying BODMAS, we can solve the expression as:

= [[5×{(12)}]÷{27+(−17)}][[3×{(20)}]÷{27+(−17)}]
+[{−54}÷(−6)] + [{−54}÷(−6)]
+[{9×5}÷(−3)]]

= [[60]÷{10}][[60]÷{10}]
+[9]+[9]
+[{45}÷(−3)]

= [6][6]
[9]+[9]+
+[−15]

= [36] + [18] + [−15]

= 36 + 18 - 15 = 39


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