Solve:
[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]
39
[[5×{(−3)×(−4)}]÷{27+(−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]
Applying BODMAS, we can solve the expression as:
= [[5×{(12)}]÷{27+(−17)}][[3×{(20)}]÷{27+(−17)}]
+[{−54}÷(−6)] + [{−54}÷(−6)]
+[{9×5}÷(−3)]]
= [[60]÷{10}][[60]÷{10}]
+[9]+[9]
+[{45}÷(−3)]
= [6][6]
[9]+[9]+
+[−15]
= [36] + [18] + [−15]
= 36 + 18 - 15 = 39