We know that the solution of the quadratic equation ax^2+bx+c=0 is given by x= b±√(b^2 4ac)2a 5x 4x^2+3=0 4x^2 5x 3=0 x= ( 5)±√(( 5)^2 ...

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Quadratic Formula

Solve : 5x ...

Question

Solve : $5 x - 4 x^{2} + 3$

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Solution

We know that the solution of the quadratic equation $a x^{2} + b x + c = 0$ is given by $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$5 x - 4 x^{2} + 3 = 0$

$⟹ 4 x^{2} - 5 x - 3 = 0$

$⟹ x = \frac{- (- 5) \pm \sqrt{(- 5)^{2} - 4 (4) (- 3)}}{2 (4)}$

$⟹ x = \frac{5 \pm \sqrt{25 + 48}}{8}$

$⟹ x = \frac{5 \pm \sqrt{73}}{8}$

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