Solve $5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)$

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Solution

$5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)$

$5 x - (12 x^{2} - 20 x - 21 x + 35) = 6 - 3 (4 x^{2} - 4 x - 9 x + 9)$

$5 x - 12 x^{2} + 41 x - 35 = 6 - 12 x^{2} + 39$

$46 x - 35 = 39 x - 21$

$7 x = 14$

$x = 2$

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Similar questions

5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)

5 x - (4 x - 7) (3 x - 5) = 6 - 3 (4 x - 9) (x - 1)

\frac{9 x - 7}{3 x + 5} = \frac{3 x - 4}{x + 6}

\frac{9 x - 7}{3 x + 5} = \frac{3 x - 4}{x + 6}

\frac{4 x - (x + 7)}{3 x - (5 x - 9)} = \frac{2}{3}

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