Question

Solve: $5x-(4x+\frac{5x-4}{7})=\frac{4x-14}{3}$.

Answer 1

Given, $5x-(4x+\frac{5x-4}{7})=\frac{4x-14}{3}$

$\Rightarrow 5x-\frac{(28x+5x-4)}{7}=\frac{4x-14}{3}$

$\Rightarrow \frac{(35x-33x+4)}{7}=\frac{4x-14}{3}$

$\Rightarrow$ $3(2x+4)=7(4x-14)$ …[Cross-multiplying the denominators]

$\Rightarrow$ $6x+12=28x-98$ ...[By Distribution Law]

$\Rightarrow$ $98+12=28x-6x$ ...[Transposing $x$ terms to one side]

$\Rightarrow$ $22x=110$ ...[On simplifying]

$\Rightarrow$ $x=\frac{110}{22}$

$\Rightarrow$ $x=5$.