Solve-5 z-22-40 z- -5 z-2

The correct option is D 5z + 2 First simplify: [(5z 2)^2 + 40z ] = [25z^2 (2×5z×2) + 2^2 + 40z] = [25z^2 20z + 4+40z] 25z^2 + 20z + 4 can also be written ...

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Byju's Answer

Standard VII

Mathematics

Methods of Solving an Equation

Solve:[5 z-22...

Question

Solve:
$[{(5 z - 2)}^{2} + 40 z] \div (5 z + 2)$

2z + 5

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2z - 5

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5z - 2

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5z + 2

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Solution

The correct option is D
5z + 2

First simplify: $[{(5 z - 2)}^{2} + 40 z]$
$= [25 z^{2} - (2 \times 5 z \times 2) + 2^{2} + 40 z]$
$= [25 z^{2} - 20 z + 4 + 40 z]$

$25 z^{2} + 20 z + 4$ can also be written as ${(5 z)}^{2} + (2 \times (5 z) \times 2) + 2^{2}$

$\Rightarrow 25 z^{2} + 20 z + 4 = {(5 z + 2)}^{2}$
$[U s i n g a^{2} + 2 a b + b^{2} = {(a + b)}^{2}]$
$∴ [\frac{({(5 z - 2)}^{2} + 40 z)}{(5 z + 2)}]$ = $\frac{{(5 z + 2)}^{2}}{(5 z + 2)} = 5 z + 2$

Suggest Corrections

Solve: [(5z−2)2+40z]÷(5z+2)

The correct option is D 5z + 2 First simplify: [(5z−2)2+40z] =[25z2−(2×5z×2)+22+40z] =[25z2−20z+4+40z] 25z2+20z+4 can also be written as (5z)2+(2×(5z)×2)+22 ⇒ 25z2+20z+4=(5z+2)2 [Using a2+2ab+b2=(a+b)2] ∴[((5z−2)2+40z)(5z+2)] = (5z+2)2(5z+2) =5z+2

Solve:
$[{(5 z - 2)}^{2} + 40 z] \div (5 z + 2)$