Solve: $6 \frac{1}{3} + 2 \frac{1}{3}$

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Solution

$6 \frac{1}{3} + 2 \frac{1}{3} = (6 + 2) [\frac{1}{3} + \frac{1}{3}]$
$= 8 [\frac{2}{3}] = 8 \frac{2}{3}$

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