Given: 6≤ 3(2x 4) lt;12 6≤ 6x+12 lt;12 6 12≤ 6x+12 12 lt;12 12 ⇒ 6≤ x lt;0 ∴ x∈[ 6,0) ...

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Predecessor and Successor

Solve: 6≤-32...

Question

Solve: $6 \leq - 3 (2 x - 4) < 12$

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Solution

Given: $6 \leq - 3 (2 x - 4) < 12$
$6 \leq - 6 x + 12 < 12$
$6 - 12 \leq - 6 x + 12 - 12 < 12 - 12$
$\Rightarrow - 6 \leq x < 0$
$∴ x \in [- 6, 0)$

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