Question

Solve : $6si{n}^2\theta -11sin\theta +4=0$

Answer 1

$6{\sin }^2\theta -11\sin \theta +4=0\Rightarrow 6{\sin }^2\theta -3\sin \theta -8\sin \theta +4=0\Rightarrow 3\sin \theta (2\sin \theta -1)-4(2\sin \theta -1)=0\Rightarrow \sin \theta =\frac{4}{3},\frac{1}{2}$

Since, $\sin \theta \le 1$

So, $\sin \theta =\frac{1}{2}$