Solve: $(64)^{\frac{2}{3}} + 9^{\frac{3}{2}}$ .

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Solution

Now,
$(64)^{\frac{2}{3}} + 9^{\frac{3}{2}}$
$= (4^{3})^{\frac{2}{3}} + (3^{2})^{\frac{3}{2}}$
$= 4^{2} + 3^{3}$
$= 16 + 27$
$= 43$ .

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