Solve $6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2}$

4 a^{2} + 2 b^{2}

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5 a^{2} + 2 b^{2}

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4 a^{2} + 3 b^{2}

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2 a^{2} + 4 b^{2}

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Solution

The correct option is A $4 a^{2} + 2 b^{2}$
We have, $6 a^{2} - 3 b^{2} + 2 a^{2} + 5 b^{2} - 4 a^{2}$

$\Rightarrow a^{2} (6 + 2 - 4) + b^{2} (5 - 3)$

$\Rightarrow 4 a^{2} + 2 b^{2}$

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Similar questions

How much should $3 x y - 4 a^{2} + 5 b^{2} + 2$ be increased to get $- 5 + 4 a^{2} + 2 b^{2} - 7 x y$ ?

3 x y - 4 a^{2} + 5 b^{2} + 2

- 5 + 4 a^{2} + 2 b^{2} - 7 x y

[\frac{3}{4} a^{2} + 3 b^{2}] \times [4 (a^{2} - \frac{2}{3} b^{2})]

9 a^{2} + 3 b^{2} - 4 a^{2} + 2 b^{2} - 6

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