Question

Solve :

$\frac{(6x+1)}{3}+1=\frac{(x-3)}{6}$

Answer 1

$\frac{(6x+1)}{3}+1=\frac{(x-3)}{6}$

Rationalizing the denominator on LHS.

$\frac{(6x+1)}{3}+\frac{3}{3}=\frac{(x-3)}{6}$

$\begin{array}{rcl}& \Rightarrow & 6x+1+3=\frac{(x-3)}{2}\\ & \Rightarrow & 6x+4=\frac{(x-3)}{2}\\ & & \end{array}$

$\Rightarrow 12x+8=x–3$

Bringing the like terms together;

$\begin{array}{rcl}12x–x& =& -3–8\\ 11x& =& -11\\ x& =& -1\end{array}$