Given 6x2−5x−25=0
First, let us find α and β such that α+β=−5 and αβ=6×(−25)=−150, where −5 is the coefficient of x.
Thus, we get α=−15 and b=10.
Next, 6x2−5x−25=6x2−15x+10x−25=3x(2x−5)+5(2x−5)
=(2x−5)(3x+5)
Therefore, the solution set is obtained from 2x−5=0 and 3x+5=0
Thus, x=52,x=−53
Hence, solution set is {−53,52}