we have questions :
6x + 3y = 6xy ...............(1)
2x+ 4y = 5xy .................(2)
we solve these questions by elimination method , As :
now we multiply by 3 in equation 2 , and get
6x + 12y =15xy ............(3)
now we substract equation (1) from equation 3 and get
9y = 9xy
=> x = 1
and we multiply 4 in eq 1. and 3 in eq 25 we get
24 x +12y = 24 xy .............(4)
6x + 12y = 15 xy ...............(5)
now we subtract equation 5 from equation 4 and get
18 x = 9xy
y = 2
therefore , x = 1 and y = 2
(or we can directly substitute the value of x in directly in eq. 1 and can findout value of y = 2
6x1 + 3y = 6*1*y
6 = 6y -3y
=> 6 = 3y
=> 6/3 = y
=> 2 =y
answer in simple steps)