Question

Solve: $7\frac{1}{6}+2\frac{2}{3}-4\frac{2}{9}$

Answer 1

$7\frac{1}{6}$ can be written as $\frac{7\times 6+1}{6}=\frac{43}{6}$
$2\frac{2}{3}$ can be written as $\frac{3\times 2+2}{3}=\frac{8}{3}$

$4\frac{2}{9}$can be written as $\frac{4\times 9+2}{9}=\frac{38}{9}$
According to the BODMAS rule first we will add $\frac{43}{6}$ and $\frac{8}{3}$.
$\frac{43}{6}+\frac{8}{3}=\frac{43\times 1+8\times 2}{6}=\frac{43+16}{6}=\frac{59}{6}$
Now, we will subtract $\frac{38}{9}$from $\frac{59}{6}$
$\frac{59}{6}-\frac{38}{9}=\frac{59\times 3-38\times 2}{18}=\frac{177-76}{18}=\frac{101}{18}$
$\frac{101}{18}$ can be written as $5\frac{11}{18}$.