Question

Solve: $7m+\frac{19}{2}=13$

Answer 1

Step 1: Moving the constants on one side of the equation

The given expression is $7m+\frac{19}{2}=13$

When we move a positive number to the other side of the equation, it gets negative.

$\Rightarrow 7m=13–\frac{19}{2}$

Step 2: Solving the R.H.S by taking the L.C.M of the denominator

$\Rightarrow 7m=13–\frac{19}{2}$

$\Rightarrow 7m=\frac{26–19}{2}$

$\Rightarrow 7m=\frac{7}{2}$

Step 3: Moving the coefficient of the variable to the right hand side

$\Rightarrow m=\frac{1}{7}\times \frac{7}{2}$

$\Rightarrow m=\frac{1}{\cancel{7}}\times \frac{\cancel{7}}{2}$

$\Rightarrow m=\frac{1}{2}$

Therefore, the value of $m$ in the given variable is $\frac{1}{2}$.