The correct option is C x = -3, y = 2
7x + 11y = 1 ....... (1)
8x + 13y = 2 ....... (2)
Multiplying Equation (1) and Equation (2) by 8 and 7 resepectively, we have
56x + 88y = 8 and 56x + 91y = 14
Subtracting the second equation from the first, we get
-3y = -6, i.e., y = 2
From Equation (1), x=1−11(y)7=1−11(2)7=−3
∴ x = -3 and y = 2