(7x + 3) (7x 3 ) #160; now (a+b) (a b) = #160; a^2 b^2 ⇒ (7x)^2 (3)^2 ⇒ 49x^2 9 ...

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Expansion of (x^2 - y^2)

Solve: 7x+37...

Question

Solve:
$(7 x + 3) (7 x - 3)$

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Solution

$(7 x + 3) (7 x - 3)$

$n o w (a + b) (a - b) = a^{2} - b^{2}$

$\Rightarrow (7 x)^{2} - (3)^{2}$

$\Rightarrow 49 x^{2} - 9$

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2 x + 6 - 7 x + 21 - 8 x - 88 = 3 x - 3 (7 x + 2)

Solve each of the following quadratic equations:
$3 (\frac{7 x + 1}{5 x - 3}) - 4 (\frac{5 x - 3}{7 x + 1}) = 11, x \neq \frac{3}{5}, \frac{- 1}{7}$

0, 1

3 (\frac{7 x + 1}{5 x - 3}) - 4 (\frac{5 x - 3}{7 x + 1}) = 11; x \neq \frac{3}{5}, - \frac{1}{7}

3 (\frac{7 x + 1}{5 x - 3}) - 4 (\frac{5 x - 3}{7 x + 1}) = 11; x \neq \frac{3}{5}, - \frac{1}{7}

3 (\frac{7 x + 1}{5 x - 3}) - 4 (\frac{5 x - 3}{7 x + 1}) = 11, x \neq \frac{3}{5}, - \frac{1}{7}

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