Solve: $7 x + 3 \leq 5$

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Solution

given, $7 x + 3 \leq 5$

$\Rightarrow 7 x + 3 - 3 \leq 5 - 3$

$\Rightarrow 7 x \leq 2$

$\Rightarrow x \leq \frac{2}{7}$

$∴ x \in [- \infty, \frac{2}{7}]$

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