Question

Solve 8.

8. Three batteries of emfs 9V, 10V and 12V and internal resistances 1$\Omega$, 2$\Omega$ and 3$\Omega$ respectively are connected in parallel to each other. The combination sends current through an external resistance of 6$\Omega$. Draw the circuit diagram and find the current through 6$\Omega$ resistance and through each battery.

Answer 1

$$\begin{gathered} letthenodevoltagebeV \\ u\sin gKCL \\ \frac{V}{6}+\frac{V-9}{1}+\frac{V-10}{2}+\frac{V-12}{3}=0 \\ V+6V-54+3V-30+2V-24=0 \\ 12V=108 \\ V=9volt \\ currentthrough6ohm=\frac{9}{6}A \\ currentthrough9voltbattery=\frac{9-9}{1}=0A \\ currentthrough10Vbattery=\frac{10-9}{2}=0.5A \\ currentthrough12V=\frac{12-9}{3}=1A \\ Regards \end{gathered}$$