Given, 8x 3≤ 2x+6 ⇒ 8x 3 2x 6≤ 0 ⇒ 6x 9≤ 0 ⇒ 6x≤ 9 ⇒ 2x≤ 3 ⇒ x≤32 ∴ x∈ [ ∞,32] ...

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Solving Linear Equations Using Transpose of Terms

Solve: 8x-3...

Question

Solve: $8 x - 3 \leq 2 x + 6$

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Solution

given, $8 x - 3 \leq 2 x + 6$

$\Rightarrow 8 x - 3 - 2 x - 6 \leq 0$

$\Rightarrow 6 x - 9 \leq 0$

$\Rightarrow 6 x \leq 9$

$\Rightarrow 2 x \leq 3$

$\Rightarrow x \leq \frac{3}{2}$

$∴ x \in [- \infty, \frac{3}{2}]$

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