Question

Solve $9p+16q=0;13p+2q=1$ and hence find approx. value $48p-22q$ approximately.

Answer 1

$9p+16q=0$

$=>9p=-16q$

$=>p=\frac{-16q}{9}$

$13p+2q=1$

$=>13\times \frac{-16q}{9}+2q=1$

$=>-208q+18q=9$

$=>-190q=9$

$=>q=\frac{-9}{190}$

$p=\frac{-16}{9}\times \frac{-9}{190}$

$=>p=\frac{8}{95}$

$48p-22q$

$=48\times \frac{8}{95}-22\times \frac{-9}{190}$

$=\frac{384}{95}+\frac{99}{95}$

$=\frac{483}{95}$

$\cong 5$